180=9x^2+9x

Solution for 180=9x^2+9x equation:

180=9x^2+9x

We move all terms to the left:

180-(9x^2+9x)=0

We get rid of parentheses

-9x^2-9x+180=0

a = -9; b = -9; c = +180;
Δ = b2-4ac
Δ = -92-4·(-9)·180
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6561}=81$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-81}{2*-9}=\frac{-72}{-18}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+81}{2*-9}=\frac{90}{-18}
=-5
$